If two graphs are not only similar graphs, but also the connecting lines of each group of corresponding points intersect at a point, and the corresponding edges are parallel to each other, then these two graphs are called potential graphs, and this point is called potential center. The similarity ratio at this time is also called the potential ratio.

Nature:

The corresponding points and similar centers of similar graphs are on the same straight line, and the ratio of their distances to similar centers is equal and similar. The corresponding sides of a polygon are parallel.

Use of potential: potential can enlarge or reduce a graph.

The application in your question is actually the intersection of DF and x axis.

Because when you relate the correspondence, you will find that this intersection is his potential center.

First, find the linear equation where DF is located.

Let the linear equation of DF be y = kx+b.

Bring in d (-3,2) and F( 1,-1).

De: k=-3/4，b=- 1/4。

So the linear equation of DF is y=-3/4x- 1/4.

Let y=0, then x= 1/3.

So its potential center is (1/3,0).

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