Suppose that Chinese cabbage weighs x Jin and fish weighs y Jin, then the meat is (100-x-y) Jin, and both x and y are integers.
Where x is a multiple of 10; Y is greater than or equal to 0 and less than or equal to 33.3.
100 = 0. 1x+3y+6( 100-x-y)
When y=(500-5.9x)/3 is brought into the range of y, the range of x is: greater than or equal to 67.8 and less than or equal to 84.75.
When x=70, y=29, which is consistent with the meaning of the question.
When x=80, y=9.33, which does not meet the meaning of the question.