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Math 100 yuan to buy meat
60 kg of Chinese cabbage, 29 kg of fish and meat 1 kg.

Suppose that Chinese cabbage weighs x Jin and fish weighs y Jin, then the meat is (100-x-y) Jin, and both x and y are integers.

Where x is a multiple of 10; Y is greater than or equal to 0 and less than or equal to 33.3.

100 = 0. 1x+3y+6( 100-x-y)

When y=(500-5.9x)/3 is brought into the range of y, the range of x is: greater than or equal to 67.8 and less than or equal to 84.75.

When x=70, y=29, which is consistent with the meaning of the question.

When x=80, y=9.33, which does not meet the meaning of the question.