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Mathematical problems in primary schools
◆ Math graphics problems in primary schools

Reward score: 0- analysis time: February 9, 2008 15: 18.

△-□ = 2.8, □+○ = 9.2, △+○ = △△△ So, they are △, △, □?

Questioner: the wings of a kind angel-the best answer during the probation period

Delta+○ = Delta Delta Delta, and you can get ○ = 2 Delta by subtracting Delta from both sides at the same time.

Convert □+○=9.2 to □+2△=9.2.

Using formula 1+ formula 2,

δ-□+□+2δ= 2.8+9.2

3△= 12

△=4

According to △=4 and ○=2×4=8.

4-□=2.8,

□= 1.2

Respondent: Manager Ye Tianjiao, Level 4 2-4 15: 14.

◆ Solve the problem of mathematical graphics in primary schools

Reward score: 5- Analysis time: 2005-12-14 23:16.

A rectangle, if its length increases by 2 cm and its width increases by 5 cm, then its area increases by 60 cm 2, which is exactly a square. How many square centimeters was the original rectangle?

Want the process, thank you!

Supplementary question: Thank you for your answer! Because my topic is wrong and I don't want to solve it. I need a calculation method to do this problem. I am a primary school student, thank you again for your help!

Questioner: Bewon-the best answer for a first-class magic apprentice.

Let the length be a and the width be b.

a+2=b+5

(a+2)(b+5)=ab+60

The solution is a=8 b=5.

ab=40

The original rectangular area is 40 square centimeters.

Respondents: Battle _ II- Manager Level 512-14 22:16.

◆ Solve the problem of mathematical graphics in primary schools

A rectangle, if its length increases by 2 cm and its width increases by 5 cm, then its area increases by 60 cm 2, which is exactly a square. How many square centimeters was the original rectangle?

Want the process, thank you!

12 accompanying children

Best answer-Voted by voters at 03: 54: 43 June 2008.

Let the length be a and the width be b.

a+2=b+5

(a+2)(b+5)=ab+60

The solution is a=8 b=5.

ab=40

The original rectangular area is 40 square centimeters.

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