I don't understand the second question.

The answer to the third question is that when m is not equal to 1, X is equal to 3 [2 plus or minus the root sign (1-m)], and when m= 1, there is no pole.

The solution of the first problem is, as long as you bring the point, (1, 1) into an equation about abc, and (2,-1) into another one, and then take the derivative of the quadratic function, there will be no C. Then, because the slope of the tangent is 1, the derivative result is equal to 60.

Three problems are also derivatives. After taking the derivative of g(x), an equation about x is obtained. Note that the slope of the function (that is, the derivative result) is equal to 0 at the pole, so it becomes a quadratic equation about X, and it is enough to solve the equation. However, it should be noted that when the derivative result is zero, the point is not necessarily the pole (such as the third power of y =), so the equation after the first derivative is needed again.

It can be guessed that the second question is also a derivative question, and the landlord ponders it himself.