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Solve discrete mathematical problems
Question 3, prove to be a group, and meet the following four conditions at the same time.

1, off (obvious)

2, the legal connection

(a * b)* c =(a+b-2)* c = a+b-2+c-2 = a+b+c-4

a *(b * c)= a *(b+ c-2)= a+b+ c-2-2 = a+b+ c-4

Then (a*b)*c=a*(b*c)

3. The unit element exists, which is 2, because a * 2 = 2 * a = a

There is an inverse element, a=4-a, because a*(4-a)=2.

Question 6

Obviously, the identity element is an idempotent element of a group.

By reducing to absurdity, suppose there is a non-unit element a (a≠e, e is a unit element), which is also an idempotent element in a group.

And then a? =a

Multiply both sides of the equation by a at the same time and you get

Answer? *a=a*a

Answer? *a=e

namely

a*(a*a)=e

therefore

a*e=e

that is

a=e

This contradicts the assumption of a≠e, so the idempotents in a group are unique.