As shown in the figure, if A turns two times, B turns seven times and C turns five times, what should be the minimum number of teeth of three gears? (PS: The picture shows three gears with different sizes. A gear is the largest, B gear is the smallest, and C gear is smaller than A gear and larger than B gear ... The order of gears in the figure is: A gear is on the far left, B gear is in the middle, and C gear is on the far right. )

7*5*2=70, and then divide 70 by the number of revolutions of each gear to get the minimum number of teeth.

70/2=35

70/7= 10

70/5= 14

The number of teeth of the three gears shall be at least 35, 10 and 14 respectively.

The second question:

Three villages, A, B and C, build a road, and the ratio of roads built by the three villages is 8:7:5. Now the three villages are required to send labor according to the repaired road. Because of special reasons, village C didn't send labor, but it needs to pay the labor remuneration of village A, village B and village C * * 1350 yuan, so there are 60 people in village A, 40 people in village B and two in village A and village B (PS: Write the process, you can set the equation, but don't set two unknowns.

60+40 = 100 (person)

8+7+5=20

100× 8/20 = 40 (person)

100× 7/20 = 35 (person)

60-40 = 20 (person)

40-35 = 5 (person)

20∶5=4∶ 1

4+ 1=5

1350× 4/5 = 1080 (yuan)

1350× 1/5 = 270 (yuan)

Answer: Village A gets 1080 yuan, and Village B gets 270 yuan.