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The Preliminary Solution of Combinatorial Mathematics
This uses the knowledge and formula of permutation and combination.

First, put five balls into five boxes, one of which has A5/5 method, that is, 5*4*3*2* 1= 120 method, and at least two balls have the same labels as the paper box, that is, two, three, four and five balls are the same. Then this method requires that there are exactly two balls and the label of the carton is the same. Then the remaining three balls must be different. They have two arrangements, so C5/2*2=20. When the three balls are the same, there is only one arrangement for the remaining two balls, so there are C5/3= 10 kinds, making a total of * * * five balls. Four identical and five identical results are the same, so there is only one arrangement method, so it is always * *.