Verification: AD= half EF
(e, f are all outside the triangle ABC, and AEF also forms a triangle)
2. a point d in the equilateral triangle ABC, BD=AD.
PB=AB,∠DBP=∠DBC,
Find the degree of ∠BPD
(P is a point outside AC, and PDB also forms a triangle)
3. In the triangle ABC, ∠BAC = 2 ∠ b. AB=2AC .AE is the bisector of ∠ BAC.
Prove that ∠C is a right angle.
(e) In CB, you can use truncation to make up for your own shortcomings)
4. In the triangle ABC, AD bisects ∠BAC, CE is perpendicular to AD and EF‖BC.
Verification: CE divides the Fed equally.
(e is on AB, even ED)