(2) Master B makes 7-2=5 more chairs than tables every day;

(3) Now imagine that the two of them will make watches in 20 days, and they should make 20*(2+3)= 100 sheets;

(4) But actually the number of desks and chairs is 134. The extra 34 figures should be caused by Master A and Master B making chairs instead of tables within a certain number of days.

(5) Now the problem becomes that A does it six times a day, and B does it five times a day, making a total of 34 times. Ask A how many days and B how many days; Because an integer is needed, 34=24+ 10=4*6+2*5, so A did it for 4 days and B did it for 2 days.

(6) Back to the original question, I know that A has been a chair for four days and B has been a chair for two days, so the number of chairs =4*9+2*7=50.

The number of tables is 84.

My answer should be the most comprehensive, because they are all arithmetic methods and there are no unknowns. This kind of problem can be solved by setting an unknown number, but why should it be put on the primary school question? The reason is to train pupils' logical reasoning ability.