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Please help me solve the math problems (7 in total) (one row)
1, there are always two kinds of cars, and there are three schemes, which can only be full rent A, full rent B, or both A and B.

Full rent A: The number of vehicles is 27/8=3.375, so we have to rent 4 vehicles, and the transportation fee is 4*300= 1200 yuan;

Full rent B: Then the number of vehicles needed is 27/4=6.75, so we have to rent 7 vehicles, and the transportation fee is 7*200= 1400 yuan;

Both Party A and Party B rent: The analysis shows that Party A's freight is 300/8 and Party B's freight is 200/4, which means that Party A rents three cars and the other three can rent one car. Freight =3*300+200= 1 100 yuan.

2. There is a relationship between them: the number of people in workshop 1 minus one fifth is equal to the number of people in workshop 2 plus one fifth of workshop 1. This means that workshop 2 is three-fifths of workshop 1, so workshop 1 is 5: 3 compared with workshop 2.

3. 1200-740=460 (person)

If there are x chickens, there are 30-X rabbits.

Then it is: 2X-4(30-X)=80 and X=20.

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