The cube of x =x3 ... and so on.
1:( 1)5a
(2) the square of a and the square of b =(a2b2)
2:( 1)a+b/ab
(2)- 1/6x
(3) 4ab+b/4a2 (the square of a)
3:
( 1)4m/(m+n)(m-n)
(2)
- 1/x+ 1
(3)- 1/x2+x
(4) 1/a- 1
4:
Solution: 3x/(x-3) +x/x-3 squared.
=3x/(x-3) squared +x2-3x/(x-3) squared.
=x2/(x-3) squared
When x=-2
Original formula = the square of x2/(x-3)
=4/5
5:( 1)
- 1
2 /x-2.
6. The solution is that the original character is (x-2).
300/x-2-300/x
= 300 /x2-2x-300 -600 /x2-2x
=600/x2-2x
Answer: It is 600/x2-2x less than the original allocation.