The cube of x =x3 ... and so on.

1:( 1)5a

(2) the square of a and the square of b =(a2b2)

2:( 1)a+b/ab

(2)- 1/6x

(3) 4ab+b/4a2 (the square of a)

3:

( 1)4m/(m+n)(m-n)

(2)

- 1/x+ 1

(3)- 1/x2+x

(4) 1/a- 1

4:

Solution: 3x/(x-3) +x/x-3 squared.

=3x/(x-3) squared +x2-3x/(x-3) squared.

=x2/(x-3) squared

When x=-2

Original formula = the square of x2/(x-3)

=4/5

5:( 1)

- 1

2 /x-2.

6. The solution is that the original character is (x-2).

300/x-2-300/x

= 300 /x2-2x-300 -600 /x2-2x

=600/x2-2x

Answer: It is 600/x2-2x less than the original allocation.