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The math problem of the fourth grade in the next semester moves the decimal point of a number to the left, and the number obtained is 27 less than the original number. What is the original number?
A: It should be thirty.

Exercise: 10- 1 = 9

27÷9=3

3× 10=30

Solution: The original number is ten times the new number, that is, the original number is nine times more than the current number, 27 is nine times, 1 times is 3, the new number is 3, and the original number is 30.

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