√3( 1+cos2x)+sin2x-√3 = sin2x+√3 cos2x

Minimum positive period = 2 (1/2 * sin2x+√ 3/2 * cos2x) = 2sin (2x+π/3) f (x); T=π(2) is derived from 2kπ-π/2 ≤ 2x+π/3 ≤ 2kπ+π/2 and k ∈ z: kπ-5π/12 ≤ x ≤ kπ+π/12. The monotonic increasing interval of k∈Z∴f(x) is 2f(x) = sin (2x-[π/4])-2 √ 2 (sin2) x = √ 2/2 * sin2x-∴ 2/24) when ≤1∴ 2x.