The normal speed of the third ship on this route is X.
3/5÷x =( 1-3/5)÷(x- 10)
3(x- 10)=2x
x=30
The normal speed of this ship on this route is 30 knots.
The distance between Party A and Party B is 125km. From Party A to Party B, some people ride cars and others ride bicycles. Bikes leave 4 hours earlier than cars and arrive 1/2 hours later. It is known that the ratio of cycling speed to cycling speed is 2: 5. What are the speeds of bicycles and cars?
Let the self-help speed be x km/h, then the riding speed is 5x/2km/h.
Then the bus ride time is:125 ÷ 5x/2 = 50/x.
Then there is the equation: 125/x-50/x=4.5 (according to the time difference between riding and riding).
The solution is x = 50/3 km/h.
Then the speed is: 5/2 * 50/3 =125/3 km/h.
A motorcade plans to transport m tons of goods in t days. If n tons have been transported, (n is less than m), the number of days of remaining goods transportation is t 1=__, and the average tonnage of goods shipped every day is a=____.
Daily freight volume: metric tons
Then the number of days required to transport the surplus goods is: (m-n) ÷ m/t = (m-n) * t/m.
A = metric tons
It takes the same time for a ship to sail 80 kilometers downstream and 60 kilometers upstream. Given the speed of the current of 3 km/h, find the speed of the ship in still water.
Let the speed of the ship in still water be x,
Then the downstream speed is x+3.
The upstream speed is x-3.
Then it is: 80/(x+3)=60/(x-3)
Solve the equation, x = 21km/h.