Generally, this kind of problem is to find out how to rent a car most cheaply, and the method of teaching materials is tabular method. Start with the big car, start with the 0 big car, and see how many cars you need to take; Then look at 1 cart and how many cars are needed until there are 0 cars. Through the comparison of several schemes, the scheme with the least empty seats and the least rent was found.

This car rental problem is an example in three math books. There is no complete answer to the example, only an incomplete solution. This textbook published by Beijing Normal University is really full of loopholes! No way, children can only teach a little with this textbook.

Starting with cart 0, there are 4 carts when cart 0 is used, which can seat 48 people, meeting the number requirements. Rent 480 yuan, which is the scheme of 1. According to this idea, there are four schemes. After comparison, the third option is the most economical, renting two big cars, 1 small car.

If we are 40 people, how to rent a car is the most economical? If you are interested, you can calculate it! Look at the picture at the end of the answer!

03 quick problem solving method

Because of this kind of problem, try to use a big car, and the rest use a small car, which is the best solution to ensure the least empty seats and the least rent.

Actually, it is mainly solved by division. The total number of people 48 divided by the limited number of people per vehicle 18 is equal to the remaining 12 people of two vehicles. The total number of people divided by each cart 12 people is equal to 1 car. Therefore, renting two big cars, 1 car is the most economical.

Shopping cart: 48÷ 18=2 (cars) ... 12 (people)

Trolley: 12÷ 12= 1 (vehicle)

Answer: Rent two big cars, and the car of 1 is the most economical.