y = 8sin[(x/4)-(π/8)]= 8sin[( 1/4)*(x-π/2)]
The image of the above function is y=sinx. First move π/2 units to the right, then expand the abscissa by 4 times and the ordinate by 8 times.
(2)y =( 1/3)sin[3x+(π/7)]=( 1/3)sin[3 *(x+π/2 1)]
The image with y=sinx is shifted to the left by π/2 1 unit, and then the abscissa is enlarged by 3 times, and the ordinate is reduced to 1/3 times.