Solution: As shown in the figure, extend AB sideline to point C, and CB=BA. According to the formula of potential difference in uniform electric field, U=Ed, the potential at point C is 0, which is equal to the potential at point O. COnnecting Co is an equipotential line, which is perpendicular to Co and points to the lower left, which is the electric field line.

Because CB=BA, we can get ∠ COB = 60 and ∠ EOA = 120 according to mathematical knowledge, that is, the included angle between the direction of electric field intensity and the positive direction of X axis is 120.

e = ubo bccs 30 = 33×32× 100？ 2 = 200 volts/meter

So the answer is: 200V/m, 120.