PH//AB,PT//AD,PH=AT=9,PT=AH=3,
MH/AM=PH/AN,MH=AM-AH=AM-3,
Let AM=y, then:
(y-3)/y=9/x,
y=3x/(x-9).
Is an algebraic expression of AM.
mn^2=am^2+an^2=[3x/(x-9)]^2+x^2
The area of the screen MNEF is s = Mn * ne = Mn * (16/9mn) =16/9 * Mn2.
= 16x^2/(x-9)^2+ 16/9*x^2
= 16x^2/9*[ 1/(x-9)^2+ 1]
Domain: 9