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Reflections on solving six problems in mathematics
1. Assuming that Party B has completed all the work within 20 days, then * * * has done115× 20 = 4/3-1=1/3.

Party A works less than Party B every day115-1/40 =1/24. Party A works first 1/3÷ 1/24=8 days.

2.*** Time 2 ÷ (112+1/24+1/8) = 8 days.

The workload of warehouse A is112× 8 = 2/3. The workload of warehouse C is 1-2/3= 1/3.

The working time between Party C and Party A is 1/3÷ 1/8=2 and 2/3 days.

The time for Party C to help Party B is 8-2 and 2/3=5 and 1/3.

3. The workload of Party A stopping work for 2 days = the workload of Party B working 6-5 days more than planned.

The work efficiency ratio of Party A and Party B is (6-5): 2 = 1: 2.

1/5 ÷ (1+2) =11515×1=1/5 A effect.

1÷115 =15 days, the time required for a person to do it.