Problem-solving ideas: Assuming all boys, the total score is 60× 100=6000 (points); In fact, the total score of boys is more than 100×63-6000=300 (points); The difference between a boy and a girl is: 70-60= 10 (points); So girls have 30010 = 30 (people); Then boys have 100-30=70 (people).

This question mainly examines the idea of chicken and rabbit in the same cage. The original data of chickens and rabbits in the same cage is relatively large, which is not conducive to students who are exposed to such problems for the first time to explore. Therefore, the original problem of large amount of data in similar topics can be solved by guiding students to start with simple problems and helping students to explore general methods to solve such problems.

The history of chickens and rabbits in the same cage

Chicken and rabbit in the same cage is one of the famous mathematical problems in ancient China. About 1500 years ago, this interesting question was recorded in Sun Tzu's calculation. It is described in the book that there are pheasant rabbits in the same cage, with 35 heads on the top and 94 feet on the bottom. What are the geometric shapes of pheasant rabbits?

These four sentences mean that there are several chickens and rabbits in a cage. From the top, there are 35 heads, and from the bottom, there are 94 feet. How many chickens and rabbits are there in each cage?

The essence of this problem is a binary equation. If the teaching method is proper, primary school students can understand the concepts of unknowns and equations and exercise their ability to abstract numbers from application problems. Generally, in the fourth to sixth grades of primary school, the content of one-dimensional linear equation is used to teach.