Similarly, fy (y) = ∫ (y, 1) f (x, y) dy = 4y (1-y? ),0 & lty & lt 1; FY(y)=0, and y is other.
② Seek the expected value. According to the definition, there is E(X)=∫(0, 1)xfX(x)dx=4/5. E(Y)=∫(0, 1)yfY(y)dy=(0, 1)4y? ( 1-y? )dy=8/ 15 .
E(XY)=∫(0, 1)∫(0,x)xyf(x,y)dxdy=∫(0, 1)dx∫(0,x)xyf(x,y)dy=8∫(0, 1)x? dx∫(0,x)y? dy=(8/3)∫(0, 1)(x^5)dx=4/9。
For reference.