Solution: c = [-10-9];

a =[6 5； 10 20; 1 0];

b =[60； 150; 8];

aeq =[]； beq =[]；

vlb =[0； 0]; vub =[]；

[x，fval]=linprog(c，A，b，Aeq，beq，vlb，vub)

Operation result: > > xxghzy 1 Optimization terminated successfully.

x =6.4286 4.2857

fval =- 102.857 1

( 1):

(2): Solution: c = [-11-9];

a =[6 5； 10 20; 1 0];

b =[60； 150; 8];

aeq =[]； beq =[]；

vlb =[0； 0]; vub =[]；

[x，fval]=linprog(c，A，b，Aeq，beq，vlb，vub)

Running results:

Optimization terminated successfully. x = 8.0000 2.4000

Fval =-109.6000 It can be seen that the production plan should be changed.