Current location - Training Enrollment Network - Mathematics courses - Solve primary school math problems
Solve primary school math problems
(1) 1 and 59? ; 2 and 58? ; 3 and 57? ; 4 and 56? ; 5 and 55? ; 6 and 54? ; 10 and 50? ; 12 and 48? ; 15 and 45? ; Twenty and forty? A group of *** 10?

(2)60=2*2*3*5,84=2*2*3*7?

Only 5 is different from 7, which means that the greatest common divisor of these two numbers is 2*2*3= 12?

The least common multiple of these two numbers is 84- 12=72?

Let these two numbers be 12a and 12b(a, b coprime) respectively.

So 12a+ 12b=60?

a+b=5?

And 5= 1+4=2+3?

1* 12= 12,4* 12=48,2* 12=24,3* 12=36?

After testing, these two numbers are 24 and 36 respectively.

(3) no?

(4) The greatest common divisor refers to the greatest common divisor of some integers * * *?

Example:? Of 2, 4 and 6, 2 is the greatest common divisor of 2, 4 and 6. ?

The least common multiple, for two integers, refers to the minimum multiple of two numbers * * *?

When calculating the minimum common multiple, the maximum common factor is usually used to assist the calculation. ?

The key to this problem lies in the decomposition of 180?

180=3×3×2×2×5? = 12? x? 15?

Guess the greatest common divisor is 3 and the least common multiple is 60.

The two numbers are 12 and 15? , so the larger number is 15?

(5) no?

12? =? 3? x? 4? 15? =? 3? x? five