Proved as follows:
Let log(a)b=n, then b = a n n, then log (c) b = log (c) an n = nlog (c) a.
So the formula on the left =n,
And the formula on the right = nlog (c) a/[log (c) a)] = n.
Therefore, the bottom-changing formula is established.
So: log (14) 7 = [㏒ (35) 7]/[㏒ (35)14]
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