So,

b=ac=2,a=bc^2=(x- 1)^2+(y-0)^2,c=ab^2=(x+ 1)^2+(y-0)^2

There is another condition, 2 * 2 = [(x- 1) 2+(y-0) 2] radical sign +[(x+ 1) 2+(y-0) 2] radical sign.

Please simplify the rest by yourself.