Solution: ∵ABCD is rectangular.
∴∠A=∠D=∠ABC=∠DCB
∴△ APB and△ PDC are right triangles.
∫△PHF is a right triangle.
∴△ APB, △ PDC and △ PHF are all right triangles.
Let AP be x, then PD =10-X.
∴BP？ =X？ +4? ，PC？ =( 10-X)？ +4?
BC? = 10? = 100
△ PBC is a right triangle.
∴X？ +4? +( 10-X)？ +4? = 100
∴X？ - 10X+ 16=0
∴X？ - 10X+25-25+ 16=0
∴(X-5)？ =9
∴X-5= 3
X = 8 or 2
A: Yes, the AP length is 8 or 2.