(m+2)/(n+3)=3/4 ( 1)
1 & lt; (m+3)/(n+ 1)& lt; 2 (2)
N-2
4m = 3n+ 1 (3) is obtained from (1) with1< n <; nine
so 4 < 3n+ 1 & lt; 28, 1 & lt; M< seven
From (3), there is n = (4m-1)/3 = m+(m-1)/3.
Obviously, m- 1 is divisible by 3, while 0
M- 1 can only be 3, so m=4.
n=4+ 1=5
This score is 4/5.