= 1/2- 1/2 cos 2 wx+√3/2s in2 wx

= 1/2+sin(2wx-π/6)

π=2π/2w

Solution: w= 1

So: f(x)= 1/2+sin(2x-π/6)

(2)f(x)+f(x+2)= 2sin(π/4x+π/4)+2sin(π/4x+π/2+π/4)

=2sin(π/4x+π/4)+2cos(π/4x+π/4)

=2√2cos(π/4x)

Therefore, when x=-2/3, the maximum value of f(x)+f(x+2) is obtained; Its value is -√6/3.

When x=-6, the minimum value of f(x)+f(x+2) is obtained; Its value is -2√2.