Let the expression of straight line AB be y=kx+b(k≠0),
Available? K=33，B = 2。 So the expression of straight line AB is y = 33x+2.
You can get ∠ Bao = 30, ∠∠BAC = 60,
∴∠CAO=90。
In Rt△BAO, we can know from Pythagorean theorem that AB = 4.
∴ AC = 4。 Point c (-23,4).
(2)∵ Points C and M are in the second quadrant, and the area of △ABM is equal to the area of △ABC.
∴CM∥AB.
Let the expression of the straight line CM be y=33x+m, and point C (-23,4) is on the straight line CM.
Available? m=6。
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