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Find the area of shadow part in the second volume of mathematics in grade six
Shadow area = left triangle+right quarter circle-left eighth circle-right isosceles right triangle

Left triangle = this parallelogram ÷2=4x4÷2=8cm?

Quarter circle area =4? x3. 14÷4= 12.56cm?

Left eighth 1 circle area =4? x3. 14÷8=6.28cm?

Right isosceles right triangle area =4x4÷2=8cm?

The final shadow area =8+ 12.56-6.28-8=6.28cm?