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Answers to the New Curriculum Standard Mathematics Newspaper of People's Education Press 13.
Each inner angle of a regular octagon is ((6-2)× 180)/8= 135 (degrees).

The area of the triangle OAB is s = (1/2) × 5× 5× sin (135 degrees).

= (25/2) × sin (45 degrees) =(25√2)/4

So the area of a regular octagon is 8S=50√2 square units.