1.

When x= 1/20 1 1, (1-x 2)/(1+x 2) = [1-(1/20).

When x=20 1 1, (1-x2)/(1+x2) = (1-20112)/(65432)

These two figures add up to 0.

And so on:

When x= 1/20 1 1, the sum of the score and the score when x=20 1 1 is also 0. ...

And when x= 1, (1-x 2)/(1+x 2) = (1-12)/(1+/kloc-0)

Then the result adds up to 0.

2.

∵a^2+4a+ 1=0

∴a^4+4a^3+a^2=0, 19a^3+76a^2+ 19a=0,-a^2-4a- 1=0

∵(a^4+ma^2+ 1)/(3a^3+ma^2+3a)=5

∴a^4+ma^2+ 1=5(3a^3+ma^2+3a)= 15a^3+5ma^2+ 15a

∴a^4- 15a^3-4ma^2- 15a+ 1=0

∴(a^4+4a^3+a^2)- 19a^3-(4m+ 1)a^2- 15a+ 1=0

∴ 19a^3+(4m+ 1)a^2+ 15a- 1=0

∴( 19a^3+76a^2+ 19a)+(4m-75)a^2-4a- 1=0

∴(4m-75)a^2-4a- 1=0

∵-a^2-4a- 1=0

∴4m-75=- 1

∴4m=74

∴m=37/2.

Are you satisfied, landlord?