PB=5-X
OB=2X
(5-X)*2X*( 1/2)=4
(X-4)*(X- 1)=0
X=4 or X= 1
Because 2X is less than or equal to 7 cm
So X= 1.
2. Let the length of PQ after x seconds be equal to 5cm.
PB=5-X
BQ=2X
PQ^2=PB^2+BQ^2
(5-X)^2+4X^2=25
X=2 or X=0.
If x is 0, PQ=AB, it does not exist, △PBQ.
So X=2.
Step 3: No.
If the area is equal to 7,
(5-X)*2X*( 1/2)=7
5X-X^2-7=0
(X-2.5)^2=-0.75
No answer
So it can't be equal to 7 square centimeters.