Find the coordinates of point d first, and then write the AD equation to find the coordinates of p.

The slopes of BD and BC satisfy kBD*KBC=- 1.

So, KBD=3/2.

So the straight BD equation is 3x-2y+8=0.

Because point D is on a circle with B as the center and r=BD=√52.

Cycle b equation: x? +(y-4)？ =52

The coordinates of point D can be solved by simultaneous circle B equation and straight line BD equation.

D(-4，-2)

So the straight line ad: y = (1/4) (x-4)

Find P(0,

- 1)

(3)

Obviously, this angle is not a fixed value.

Because in the process of e moving to the left, in order to ensure AE+OF=EF,

Point f must move down.

So ME rotates clockwise and MF rotates counterclockwise.

The angular electromotive force must have decreased.