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Missed math problems
abc+acb+bac+bca+cab+cba=5328

Because it is three digits, it can be broken down into lists.

100 a+ 10b+c+ 100 a+ 10c+b …………= 5328

Tidy up

222a+222b+222c=5328

a+b+c=24

A, b and c are not equal, and none of them are 0.

That is to say, a, b and c are three numbers in 1~9.

Ask what the minimum quantity is.

If three numbers are equal, 24/3=8.

But the three numbers are different, and the largest number is already the number 9.

So the minimum should be 789.