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Super brain's math problems
Connecting advertisements, making DE⊥AB, hanging feet E,

∵& lt; AMB=75,& ltDMC=45,

∴<; AMD = 180-& lt; AMB-& lt; DMC=60,

AM = DM,

∴△AMD is equilateral,

∴AD=AM,

∵DE⊥AB,CB⊥AB,

∴DE//CB,

Similarly, CD⊥BC,EB⊥BC,

∴BE//DC,

∵& lt; DCB=90,

The quadrilateral BCDE is a rectangle,

∴DE=BC,

∵& lt; BAM=90 -75 = 15,

& ltMAD=60,

∴<; EAD = & ltBAM+& lt; MAD=75,

∴<; EAD = & ltBMA=75,

∵& lt; ABM = & ltDEA=90,

∴RT△AED≌RT△MBA,

∴AB=DE,

∴AB=BC.