Beijing normal university printing plate ninth grade second volume mathematics exercise 2.8 answer to the third question</p><p>Let one side of the rectangle be GE=FH=X and the area of the rectangle be

Beijing normal university printing plate ninth grade second volume mathematics exercise 2.8 answer to the third question

Let one side of the rectangle be GE=FH=X and the area of the rectangle be

Beijing normal university printing plate ninth grade second volume mathematics exercise 2.8 answer to the third question

Let one side of the rectangle be GE=FH=X and the area of the rectangle be y.

∫△ CEG △△ HFB △ cab

Is that?

CE = 3/4 times

At the same time, namely?

FB=4/3x

EF = BC-CE-FB = 50-3/4x-4/3x = 50-25/12 * x (due to Pythagorean theorem BC=50).

y=GE*EF=x(50-25/ 12*x)

When x=0, the maximum value of y =300.