Log<A n > b = log & lta & gtb/n=( 1/n)log<a & gtb.②
Log<A>M log<B>N = log<B>M/log <; b & gta* log & lt; a & gtn/log & lt; a & gtb = log & lta & gtNlog & ltb & gtM.③
By log
A (log<a>N * log<a>m)
=[a^log<; a & gtn^log<; a & gtM
=n^log<; a & gtm,
Similarly, a (log
∴N^logaM=M^logaN ④
Log<N & gtM=(logaM)/(logaN). ⑤
Proof: let m = n b, and then logarithm
∴log<; N & gtM = b = log & lta & gtm/log & lt; A> noun (abbreviation of noun)
(2) With logarithm as exponential power, the base of logarithm and real number can be transposed. See ④.
The product of two logarithms, real numbers are interchangeable. See ③
When the base is the same, the ratio of two logarithms has nothing to do with the base. (changed the topic) See ⑤.