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Three problems of proportional mathematics in the sixth grade of primary school.
The first question is multiplied by the area ratio of 12: 10: 6 and is set as12k/0k6k, so12k+10k+6k = 280 28k =/kloc.

So the area is 120 100 60.

The second question is set for X sheets.

(96-x)/(80+x)=3/8 diagonal multiplication 240+3x = 768-8x8x = 48.

The third table 9a stool 7a

9a-7a=20

So a= 10

So this table has 90 chairs and 70 stools.