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Jiangsu sanshang mathematical calculation
The fourth power of-1-(1-0.5) × (1/3 )× [2-(the third power of-)]

=- 1^4-( 1-0.5)×( 1/3)×[2-(-3^2)]

=- 1- 1/6× [2-(-9)]

=-1-1/6×11(Note that when there is a negative sign in front of the brackets, remove the brackets and change the number).

=- 1- 1 1/6

=- 17/6

According to your description, it is the answer above. If "the fourth power of 1" is (-1) 4, "(the third power of 3) 2".

The answer is as follows:

The fourth power of-1-(1-0.5) × (1/3 )× [2-(the third power of-)]

=(- 1)^4-( 1-0.5)×( 1/3)×[2-(-3)^2)]

= 1- 1/6×[2-9]

= 1- 1/6×(-7)

=- 1+7/6

= 1/6

36* ( 1/2- 1/3) ÷ 1/2

= 36 * (1/6) ÷ 1/2 (calculated in brackets first according to the law)

= 6 ÷ 1/2 (when all operations are multiplication and division, they should be calculated in sequence)

=6*2

= 12

Jiangsu Wu Yunchao answered for reference!