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The ~ ~ ~ column solution of primary school mathematics problems
1.

From "A is two fifths more than B", we can know that A: B is 7: 5, and from "B's deposit is 1 1 4 times of A's", we can know that A: B = 14: 25!

Original A: B = 35: 25

and

Compared with Party A (after Party A withdraws money), Party B = 14: 25, and there are 2 1 0/21=10 (RMB) "Find the amount of money represented by each copy".

Residual =10 *14 =140 (yuan)

2.

(3/4)/( 1/20+ 1/30)= 9(h)

1/20-1/30 =1/60 (A scores more than B every hour)

1/60*9=3/20

72/(3/20)=480 (total pages)

480* 1/20*9=2 16 (page a)

2 16-72= 144 (page b)