If AH is perpendicular to BC, then AB= 10, CD=8, BH=6, ad = ch = X.

X+6+X=2*(5+4)，X=6。

2

With the method of 1, Q 1O2=5.

2X+6=2*5，X=2

three

Similarly, EMN triangle is an isosceles triangle.

Then AN is perpendicular to O 1O2, e is the midpoint of AM, and X=4.