X>0, as long as the exponent is positive, the power function will increase. If the exponent is negative, the power function will decrease. So the index is the key.

Let k 2-2k-1= 0 and get k = 1 √ 2. Because the previous coefficients may affect the positive and negative of the function, it is necessary to find the dividing point of the positive and negative coefficients. Let k 2+k=0 and get k=0 or-1. Discuss according to the situation.

When 1. K = 1 √ 2, the exponent is 0 and the function becomes y = k 2+k, and the change of x does not affect the function value.

2. When k =- 1 or 0, y=0, and the function value remains unchanged.

3. when k

4.- 1 & lt； When k< 1-√2, the coefficient is negative, the exponent is positive, and the power function decreases, so the function value decreases with the increase of x.

5. 1-√2 & lt； K<0, the coefficient is negative, the exponent is negative, and the power function is increasing, so the function value increases with the increase of X.

6.0<k< 1+√2, the coefficient is positive, the exponent is negative, and the power function decreases, so the function value decreases with the increase of x.

7. When k>1+√ 2, the coefficient and exponent are positive, and the power function increases, so the function value increases with the increase of x.

Just write out the final comprehensive conclusion.