Known conditions: x is a positive integer of two digits.

Q: What is the remainder of x/3?

Let x be ten digits, and the single digits are A and B respectively.

Statement (1): A+B=5, where A can be 1, 2, 3, 4, 5, and the corresponding B is 4, 3, 2, 1, 0. Therefore, the qualified x is 14, 23, 32, 4 1, 50, and the remainder of x/3 is 2, SUFF.

Statement (2): x=9k+5(k is any nonnegative integer) = & gtX/3=3k+5/3. Since 3k is an integer, we only need to look at 5/3 remainder 2, that is, x/3 remainder 2, SUFF.

Option d