f(x)/g(x)=(x+5)/(x^2-6x-55)......................( 1)
V. Asymptote: x 2-6x -55 = (x+5) (x-11), x =1and-5.
H asymptote: from (1), the highest molecule is the first power of x, and the parent is the second power of x, because x2 >;; X, so x=0.
9.2 S 1 (t) = 700-1.4t2, the greater the t, the smaller the s1= the sales volume does not increase, while the greater the t, the greater the S2, and the sales volume increases.
So after (a), S2 was increased in 2000.
(b) Total sales = S1(t)+S2 (t) = T3+1.6t2+1200.
(c)t=0, etc. For example, in 2000 and 2006, t=6,
The program substituted in (b) = (6) 3+1.6 (6) 2+1200 = 216+57.6+1200 =1473.6.
(d) The coffee shop S12000 should be closed after the sales volume declined in 2000, and S2 can continue to operate.
Just a personal understanding of the problem, there may be mistakes, for reference only!