Liang Xiao and Xiao Hong, math problems in Grade Two, have a total of 20 yuan money. As we all know, Liang Xiao has more money in 6 yuan than Xiao Hong. How much money do they have?
Let Xiaohong have X yuan, then Liang Xiao has (x+6) yuan.
x+(x+6)=20
2x+6 =20
2x =20-6
2x = 14
x =7
X+6 = 7+6 = 13 (yuan)
A: Xiao Hong 7 yuan, Liang Xiao 13 yuan.
Or: Xiaohong: (20-6)÷ 2 = 14÷2=7 (yuan)
Liang Xiao: 7+6 = 13 (yuan)