First of all, we must correct a misunderstanding. When the peaches grabbed by the little black monkey were given to the little gray monkey, the total number of peaches taken by the four monkeys remained unchanged, all of which were 27, but when the peaches of the long-tailed monkey doubled and the peaches of the short-tailed monkey were reduced by half, the total number changed. After doubling the peaches of macaques and reducing the peaches of macaques by half, the number of peaches of the two monkeys is equal, that is to say, the number of peaches of macaques before is half of this equal number, and the number of peaches of macaques before is twice, so we can know that the number of peaches of macaques before is four times that of macaques before, and the total number of two monkeys is five times that of macaques before, which is 2.5 times that of the final equal number. Plus two other monkeys, a ***4.5 times the "final equal number". So 4.5 times the "final equivalent" equals 27, so we can calculate that the final equivalent equals 6. Knowing this number, it is not difficult to figure out how much each little monkey took at first.

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Next, I will solve the problem with the idea of setting an unknown number in the equation. What you will learn in the future is actually very simple, that is, change the unknown into the letter X. We know that the key to solving this problem is to know how many monkeys there are when there are many monkeys. Then let's assume that this equal number is X, and the little black monkey subtracts two to become X, so he had x+2 before. Little grey monkey peach has X after adding 2, so it has x-2 before. Similarly, we can know that there are 0.5x long-tailed monkeys and 2x short-tailed monkeys. So add them all up-* * * is 4.5x, 4.5x=27, and it is easy to get x=6, so there are 8 little black monkeys, 4 little gray monkeys, 3 long-tailed monkeys and 12 short-tailed monkeys.

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