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Elective Mathematics 2-3 in Senior High School
36. Use enumeration method. Let the other two sides not exceed 1 1 and be greater than 1 1. The second longest side is 1 1, so the shortest side is 1+0 1, * *1. The second longest side is 10, so the shortest side is 2- 10. By analogy, when the second long side is 6, the shortest side is 6, *** 1. 1+3+5+7+9+ 1 1=36

54. Consider the negative situation, that is, all are new players, and there are 3*2* 1=6 situations. The overall situation is 5*4*3=60 situations. 60-6=54

22. Only consider the combination of AB ***6*5=30. The five types with A=0 are the same straight line, and the calculation is repeated four times, and the five types with B=0 are repeated four times. 30-4-4=22

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