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Mathematics test in the first semester of senior one.
A, multiple-choice question 1, known sinx=54.
-and x is in the third quadrant, then tanx = a.
four
3.43.34.3
4DCB
2. known vector) 2, 1(a, then? 5.5.5.5
Dame Bath II
3.)2， 1(a，)2， 1(？ B, then ba a. (- 1, 4) b, 3 C, (0, 4) d,
three
4.)2， 1(a，)2， 1(？ The angle formed by b, ba and x is cosx=
A.3 B。
53
C.5 15 D.-5
155. In the parallelogram ABCD, the following error is a, BDABADDDBABADCACABADBBC.
AD？ ...
6. Move the image with function y=sin2x to the right by 6.
Unit, the resolution function is () (A)y=sin(2x+.
3? )(B)y=sin(2x+6？ )(C)y=sin(2x-3？ )(D)y=sin(2x-6
) 7. The value of sin5 sin25-sin95 sin65 is () (a).
2 1 (B)-2 1 (C)23 (D)-2
three
8, function y=tan(3
2?
The monotone increasing interval of x) is () (a) (2kπ-
32? ，2kπ+34？ )k？ Z (B)(2kπ-35？ ，2kπ+3
)k？ Z
(C)(4kπ-32？ ，4kπ+34？ )k？ Z (D)(kπ-35？ ，kπ+3
)k？ Z
9. Let 0
，sinα=53，cos(α-β)= 13 12
, the value of sinβ is ()
(1)
65
16 (B)6533 (C)6556 (D)6563
20 14 exam question bank for senior high school entrance examination Chinese mathematics English physical chemistry
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In 10 and △ABC, tanA=3 1 and tanB=2 are known.
1
, then ∠C equals ()
(A)30 (B)45 (C)60 (D) 135
1 1, if? Is the angle of the third quadrant and satisfies 2sin2cossin 1, then 2?
Yes ()
(a) first quadrant (b) second quadrant (c) third quadrant (d) fourth quadrant
12、y=sin(2x+2
five
A symmetric A)x=- π) looks like () (a) x =-
2
(B)x=-4？ (C)x=8？ (D)x=？ 45
13, known as 0
four
And then what? 2sin 1？ Equal to () (a) cos θ-sin θ (b) sin θ-cos θ (c) 2cosθ (d) 2cosθ.
14, function y=3sin(2x+
three
) can be regarded as () obtained by shifting the image of function y=3sin2x as follows.
(a) Translate 3 to the left? Unit (b) moves 3 to the right?
Unit (c) is translated to the left.
6? Unit (d) moves 6 to the right.
Unit 15, if sin2x >；; Cos2x, then the value range of x is () (a) {x | 2kπ-43π < x <; 2kπ+4？ ，k？ Z } (B){x|2kπ+4
& ltx & lt2kπ+45
π，k？ Z}
{x|kπ-
4? & ltx & ltkπ+4？ π，k？ Z} (D){x|kπ+4？ & ltx & ltkπ+4
three
π，k？ Z} two. Fill in the blanks:
16, and the range of the function y = cos2x-8cosx is. 17, function y = | cos (2x-
three
The minimum positive period of | is. 18, function y=sin2.
1
Enlarge the abscissa of each point on the image of X to twice the original (the ordinate is unchanged), and then translate the obtained image to the right.
three
After one unit, the analytical expression of the function corresponding to the obtained image is. 19, given the function y =-cos (3x+ 1), then its increasing interval is.
20, function y = a+bcosx (b
The minimum positive period of] is.
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Third, the solution: 20, (this is entitled 12 points) Known function f(x) = cos2x-sin2x+2sinx cosx, find the minimum positive period of f(x), what is the maximum value of f(x)?
2 1, (this question 12 points) is known), 2, (,5
three
2sinxx and (1) value xtan (2) value xsin.