Analysis: This question belongs to the mathematical arrangement problem, and the specific solution is as follows:

1. Mark these four cabbages as 1, 2, 3 and 4 respectively.

2. Because there is no requirement in the title that four cabbages should be evenly divided into two bags, there are two cases: one is two cabbages per bag, the other is three cabbages per bag, and the other is 1 cabbage.

3. So the case 1 * * * can be divided into three ways: (1, 3) and (2,4), (1, 2) and (3,4), (2,3) and (1, 3).

4. Case 2 * * * can be divided into four ways, namely (1, 2,3) and (4), (1, 3,4) and (2), (2,3,4) and (1), (650

Arrangement problem:

Take out m( 1≤m≤n) different elements from n different elements at a time and arrange them in a row, which is called non-repetitive arrangement or linear arrangement of taking out m elements from n elements, which is called arrangement for short. The number of all different permutations of m different elements from n different elements is called permutation number or permutation number.

On total replacement:

Taking any m(m≤n) elements from n different elements and arranging them in a certain order is called the arrangement of taking m elements from n different elements. When m=n, all permutations are called total permutations.